Pre-Quantum Electrodynamics

Comparison of Electrostatics and Magnetostatics ems.ms.vp.comp
  • Gr 5.3.4
Electrostatics   \({\boldsymbol \nabla} \cdot {\bf E} = \frac{\rho}{\varepsilon_0}\)   Gauss's law
    \({\boldsymbol \nabla} \times {\bf E} = 0\)   [nameless]
Magnetostatics   \({\boldsymbol \nabla} \cdot {\bf B} = 0\)   [nameless]
    \({\boldsymbol \nabla} \times {\bf B} = \mu_0 {\bf J}\)   Ampère's law



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Author: Jean-Sébastien Caux

Created: 2024-02-27 Tue 10:31